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Probability Analysis of Fried Gold Flower Cards

1. There are 52*51*50/3*2*1=22100 kinds of permutations and combinations by randomly drawing three cards out of 52 cards

2. There are 13*4=52 kinds of leopards, and the probability of occurrence is 0.24%;

3. There are (13-1)*4=48 kinds of Jinshun, the probability of occurrence is 0.22%;

4. There are 4*(13*12*11/6-12)=1096 kinds of golden flowers, and the probability of occurrence is 4.96%;

5. There are (4*4*4-4)*12=720 kinds of straights, and the probability of occurrence is 3.26%;

6. There are 4*3/2*12*4*13=3744 pairs, and the probability of occurrence is 16.94%;

7. There are 22100-52-48-1096-720-3744=16440 kinds of scattered cards and special cards, and the probability of occurrence is 73.49%;

Card type introduction

Leopard: Three cards with the same point, AAA, 222.

Straight Flush: A straight of the same suit, with 456 spades and 789 hearts.

Golden flower: the same suit, non-straight, 368 spades, 945 diamonds.

Shunzi: Shunzi with different suits, 5 of spades, 6 of hearts, 7 of diamonds.

Pair: Two cards of the same rank, 223, 334.

Disassembled: Three cards that do not form any type of card.

Special: 235 with different suits.

Victory decision

a. Leopard>Shunjin>Golden Flower>Shunzi>Pair>Single.

b. When leopards exist, "different suits 235" > "leopards".

c. AKQ >KQJ>...234>A23. Single card size: A>K>Q…..>2.

d. In the case of pairs, compare first, then single.

e. When all are single sheets, compare them sequentially starting from the largest single sheet.

f. If it is bigger than the card type, it will be negative if it is opened first.